Base | Representation |
---|---|
bin | 111110110111011100101… |
… | …001101010010101111101 |
3 | 120022000001021012001111111 |
4 | 332313130221222111331 |
5 | 1031240123333310331 |
6 | 13104351411522021 |
7 | 624056124314122 |
oct | 76673451522575 |
9 | 16260037161444 |
10 | 4320144041341 |
11 | 141618775a317 |
12 | 5993335b9311 |
13 | 2545070c591b |
14 | 10d14b940749 |
15 | 7759bd88db1 |
hex | 3eddca6a57d |
4320144041341 has 2 divisors, whose sum is σ = 4320144041342. Its totient is φ = 4320144041340.
The previous prime is 4320144041251. The next prime is 4320144041387. The reversal of 4320144041341 is 1431404410234.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4284192089241 + 35951952100 = 2069829^2 + 189610^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4320144041341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4320144045341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2160072020670 + 2160072020671.
It is an arithmetic number, because the mean of its divisors is an integer number (2160072020671).
Almost surely, 24320144041341 is an apocalyptic number.
It is an amenable number.
4320144041341 is a deficient number, since it is larger than the sum of its proper divisors (1).
4320144041341 is an equidigital number, since it uses as much as digits as its factorization.
4320144041341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 4320144041341 its reverse (1431404410234), we get a palindrome (5751548451575).
The spelling of 4320144041341 in words is "four trillion, three hundred twenty billion, one hundred forty-four million, forty-one thousand, three hundred forty-one".
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