Base | Representation |
---|---|
bin | 10011101001011000110011… |
… | …11011010010000000011001 |
3 | 12122222012210222001022100021 |
4 | 21310230121323102000121 |
5 | 21130321242304013423 |
6 | 231515230254510441 |
7 | 12046231164213511 |
oct | 1164543173220031 |
9 | 178865728038307 |
10 | 43203511001113 |
11 | 12847562713061 |
12 | 4a19168505421 |
13 | 1b150c5935588 |
14 | a950bd8b6841 |
15 | 4edc50c6695d |
hex | 274b19ed2019 |
43203511001113 has 2 divisors, whose sum is σ = 43203511001114. Its totient is φ = 43203511001112.
The previous prime is 43203511001069. The next prime is 43203511001117. The reversal of 43203511001113 is 31110011530234.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37704659529744 + 5498851471369 = 6140412^2 + 2344963^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43203511001113 is a prime.
It is not a weakly prime, because it can be changed into another prime (43203511001117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21601755500556 + 21601755500557.
It is an arithmetic number, because the mean of its divisors is an integer number (21601755500557).
Almost surely, 243203511001113 is an apocalyptic number.
It is an amenable number.
43203511001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
43203511001113 is an equidigital number, since it uses as much as digits as its factorization.
43203511001113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 43203511001113 its reverse (31110011530234), we get a palindrome (74313522531347).
The spelling of 43203511001113 in words is "forty-three trillion, two hundred three billion, five hundred eleven million, one thousand, one hundred thirteen".
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