Base | Representation |
---|---|
bin | 110001001000001100110011… |
… | …0101100010100000000000111 |
3 | 2002200001202102100101210001112 |
4 | 1202100121212230110000013 |
5 | 423120102112434141124 |
6 | 4131024200424115235 |
7 | 160010523040326653 |
oct | 14220314654240007 |
9 | 2080052370353045 |
10 | 432135562412039 |
11 | 11576773225a102 |
12 | 40572925605b1b |
13 | 1571829361c655 |
14 | 789d6895b1a63 |
15 | 34e5c8724590e |
hex | 1890666b14007 |
432135562412039 has 2 divisors, whose sum is σ = 432135562412040. Its totient is φ = 432135562412038.
The previous prime is 432135562412011. The next prime is 432135562412053. The reversal of 432135562412039 is 930214265531234.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 432135562412039 - 220 = 432135561363463 is a prime.
It is a super-2 number, since 2×4321355624120392 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (432135562412839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216067781206019 + 216067781206020.
It is an arithmetic number, because the mean of its divisors is an integer number (216067781206020).
Almost surely, 2432135562412039 is an apocalyptic number.
432135562412039 is a deficient number, since it is larger than the sum of its proper divisors (1).
432135562412039 is an equidigital number, since it uses as much as digits as its factorization.
432135562412039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4665600, while the sum is 50.
The spelling of 432135562412039 in words is "four hundred thirty-two trillion, one hundred thirty-five billion, five hundred sixty-two million, four hundred twelve thousand, thirty-nine".
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