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43214312041 is a prime number
BaseRepresentation
bin101000001111110001…
…100001001001101001
311010112200100111200121
4220033301201021221
51202000330441131
631504040403241
73056614406635
oct501761411151
9133480314617
1043214312041
111736639727a
128460476521
1340c8c92554
14213d43ddc5
1511cdcb0911
hexa0fc61269

43214312041 has 2 divisors, whose sum is σ = 43214312042. Its totient is φ = 43214312040.

The previous prime is 43214312033. The next prime is 43214312083. The reversal of 43214312041 is 14021341234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42799334400 + 414977641 = 206880^2 + 20371^2 .

It is a cyclic number.

It is not a de Polignac number, because 43214312041 - 23 = 43214312033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43214311997 and 43214312015.

It is not a weakly prime, because it can be changed into another prime (43214312641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21607156020 + 21607156021.

It is an arithmetic number, because the mean of its divisors is an integer number (21607156021).

Almost surely, 243214312041 is an apocalyptic number.

It is an amenable number.

43214312041 is a deficient number, since it is larger than the sum of its proper divisors (1).

43214312041 is an equidigital number, since it uses as much as digits as its factorization.

43214312041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 43214312041 its reverse (14021341234), we get a palindrome (57235653275).

The spelling of 43214312041 in words is "forty-three billion, two hundred fourteen million, three hundred twelve thousand, forty-one".