Base | Representation |
---|---|
bin | 101000010000010000… |
… | …100011111110100001 |
3 | 11010120020122221222111 |
4 | 220100100203332201 |
5 | 1202004421400311 |
6 | 31504531035321 |
7 | 3060043522666 |
oct | 502020437641 |
9 | 133506587874 |
10 | 43222450081 |
11 | 1736aa45528 |
12 | 846313bb41 |
13 | 40ca881765 |
14 | 214055ba6d |
15 | 11ce86bd21 |
hex | a10423fa1 |
43222450081 has 2 divisors, whose sum is σ = 43222450082. Its totient is φ = 43222450080.
The previous prime is 43222450079. The next prime is 43222450087. The reversal of 43222450081 is 18005422234.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30691886481 + 12530563600 = 175191^2 + 111940^2 .
It is a cyclic number.
It is not a de Polignac number, because 43222450081 - 21 = 43222450079 is a prime.
It is a super-2 number, since 2×432224500812 (a number of 22 digits) contains 22 as substring.
Together with 43222450079, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (43222450087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21611225040 + 21611225041.
It is an arithmetic number, because the mean of its divisors is an integer number (21611225041).
Almost surely, 243222450081 is an apocalyptic number.
It is an amenable number.
43222450081 is a deficient number, since it is larger than the sum of its proper divisors (1).
43222450081 is an equidigital number, since it uses as much as digits as its factorization.
43222450081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 31.
The spelling of 43222450081 in words is "forty-three billion, two hundred twenty-two million, four hundred fifty thousand, eighty-one".
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