Base | Representation |
---|---|
bin | 10011101010001100010000… |
… | …01010001101111010001111 |
3 | 12200001212002210110200211001 |
4 | 21311012020022031322033 |
5 | 21131244323313322111 |
6 | 231540035042241131 |
7 | 12051226464516244 |
oct | 1165061012157217 |
9 | 180055083420731 |
10 | 43231130214031 |
11 | 12858245a77561 |
12 | 4a225960561a7 |
13 | 1b178a79aab06 |
14 | a9657da635cb |
15 | 4ee81a8621c1 |
hex | 27518828de8f |
43231130214031 has 2 divisors, whose sum is σ = 43231130214032. Its totient is φ = 43231130214030.
The previous prime is 43231130213993. The next prime is 43231130214047. The reversal of 43231130214031 is 13041203113234.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43231130214031 - 215 = 43231130181263 is a prime.
It is a super-2 number, since 2×432311302140312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43231130214631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21615565107015 + 21615565107016.
It is an arithmetic number, because the mean of its divisors is an integer number (21615565107016).
Almost surely, 243231130214031 is an apocalyptic number.
43231130214031 is a deficient number, since it is larger than the sum of its proper divisors (1).
43231130214031 is an equidigital number, since it uses as much as digits as its factorization.
43231130214031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 43231130214031 its reverse (13041203113234), we get a palindrome (56272333327265).
The spelling of 43231130214031 in words is "forty-three trillion, two hundred thirty-one billion, one hundred thirty million, two hundred fourteen thousand, thirty-one".
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