Base | Representation |
---|---|
bin | 1100100101011100100… |
… | …11010110111111110001 |
3 | 1112100011011110212001021 |
4 | 12102232103112333301 |
5 | 24041044241240423 |
6 | 530352415335441 |
7 | 43145540123566 |
oct | 6225623267761 |
9 | 1470134425037 |
10 | 432421040113 |
11 | 157430449727 |
12 | 6b980b21581 |
13 | 31a14477a4a |
14 | 16d01d8686d |
15 | b3acd5295d |
hex | 64ae4d6ff1 |
432421040113 has 2 divisors, whose sum is σ = 432421040114. Its totient is φ = 432421040112.
The previous prime is 432421040087. The next prime is 432421040123. The reversal of 432421040113 is 311040124234.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 406746746289 + 25674293824 = 637767^2 + 160232^2 .
It is a cyclic number.
It is not a de Polignac number, because 432421040113 - 29 = 432421039601 is a prime.
It is not a weakly prime, because it can be changed into another prime (432421040123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216210520056 + 216210520057.
It is an arithmetic number, because the mean of its divisors is an integer number (216210520057).
Almost surely, 2432421040113 is an apocalyptic number.
It is an amenable number.
432421040113 is a deficient number, since it is larger than the sum of its proper divisors (1).
432421040113 is an equidigital number, since it uses as much as digits as its factorization.
432421040113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 432421040113 its reverse (311040124234), we get a palindrome (743461164347).
The spelling of 432421040113 in words is "four hundred thirty-two billion, four hundred twenty-one million, forty thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •