Base | Representation |
---|---|
bin | 10011101011001001100101… |
… | …00001110000001000011111 |
3 | 12200012000002021000210200021 |
4 | 21311210302201300020133 |
5 | 21132314240120000221 |
6 | 232003122014013011 |
7 | 12053503400131162 |
oct | 1165446241601037 |
9 | 180160067023607 |
10 | 43264053281311 |
11 | 12870200205275 |
12 | 4a28a43aa7167 |
13 | 1b1aa2382c205 |
14 | a97dc43a9ad9 |
15 | 5005e5dd5041 |
hex | 27593287021f |
43264053281311 has 2 divisors, whose sum is σ = 43264053281312. Its totient is φ = 43264053281310.
The previous prime is 43264053281243. The next prime is 43264053281327. The reversal of 43264053281311 is 11318235046234.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43264053281311 - 229 = 43263516410399 is a prime.
It is a super-2 number, since 2×432640532813112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43264053281341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21632026640655 + 21632026640656.
It is an arithmetic number, because the mean of its divisors is an integer number (21632026640656).
Almost surely, 243264053281311 is an apocalyptic number.
43264053281311 is a deficient number, since it is larger than the sum of its proper divisors (1).
43264053281311 is an equidigital number, since it uses as much as digits as its factorization.
43264053281311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 43264053281311 in words is "forty-three trillion, two hundred sixty-four billion, fifty-three million, two hundred eighty-one thousand, three hundred eleven".
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