Base | Representation |
---|---|
bin | 101000010100111101… |
… | …011110110001101001 |
3 | 11010202202002200112121 |
4 | 220110331132301221 |
5 | 1202140120142441 |
6 | 31520425511241 |
7 | 3062022160423 |
oct | 502475366151 |
9 | 133682080477 |
10 | 43301334121 |
11 | 17400524251 |
12 | 8485642521 |
13 | 4111010bc6 |
14 | 214ac13813 |
15 | 11d674edd1 |
hex | a14f5ec69 |
43301334121 has 2 divisors, whose sum is σ = 43301334122. Its totient is φ = 43301334120.
The previous prime is 43301334053. The next prime is 43301334127. The reversal of 43301334121 is 12143310334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41483505625 + 1817828496 = 203675^2 + 42636^2 .
It is a cyclic number.
It is not a de Polignac number, because 43301334121 - 211 = 43301332073 is a prime.
It is not a weakly prime, because it can be changed into another prime (43301334127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21650667060 + 21650667061.
It is an arithmetic number, because the mean of its divisors is an integer number (21650667061).
Almost surely, 243301334121 is an apocalyptic number.
It is an amenable number.
43301334121 is a deficient number, since it is larger than the sum of its proper divisors (1).
43301334121 is an equidigital number, since it uses as much as digits as its factorization.
43301334121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 43301334121 its reverse (12143310334), we get a palindrome (55444644455).
The spelling of 43301334121 in words is "forty-three billion, three hundred one million, three hundred thirty-four thousand, one hundred twenty-one".
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