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43303434141 = 311310844837
BaseRepresentation
bin101000010101000101…
…011111011110011101
311010202220001101020010
4220111011133132131
51202141134343031
631520542513433
73062046055062
oct502505373635
9133686041203
1043303434141
1117401729000
128486295879
134111597a16
14214b1dcc69
1511d6a17246
hexa1515f79d

43303434141 has 16 divisors (see below), whose sum is σ = 63507371328. Its totient is φ = 26244503120.

The previous prime is 43303434113. The next prime is 43303434151. The reversal of 43303434141 is 14143430334.

It is not a de Polignac number, because 43303434141 - 26 = 43303434077 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43303434099 and 43303434108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43303434151) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5418426 + ... + 5426411.

It is an arithmetic number, because the mean of its divisors is an integer number (3969210708).

Almost surely, 243303434141 is an apocalyptic number.

It is an amenable number.

43303434141 is a deficient number, since it is larger than the sum of its proper divisors (20203937187).

43303434141 is a wasteful number, since it uses less digits than its factorization.

43303434141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10844873 (or 10844851 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 30.

Adding to 43303434141 its reverse (14143430334), we get a palindrome (57446864475).

The spelling of 43303434141 in words is "forty-three billion, three hundred three million, four hundred thirty-four thousand, one hundred forty-one".

Divisors: 1 3 11 33 121 363 1331 3993 10844837 32534511 119293207 357879621 1312225277 3936675831 14434478047 43303434141