43310234117 has 2 divisors, whose sum is σ = 43310234118. Its totient is φ = 43310234116.

The previous prime is 43310234113. The next prime is 43310234159. The reversal of 43310234117 is 71143201334.

43310234117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43310188321 + 45796 = 208111^2 + 214^2 .

It is a cyclic number.

It is not a de Polignac number, because 43310234117 - 2² = 43310234113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43310234117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43310234113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655117058 + 21655117059.

It is an arithmetic number, because the mean of its divisors is an integer number (21655117059).

Almost surely, 2^43310234117 is an apocalyptic number.

It is an amenable number.

43310234117 is a deficient number, since it is larger than the sum of its proper divisors (1).

43310234117 is an equidigital number, since it uses as much as digits as its factorization.

43310234117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 43310234117 in words is "forty-three billion, three hundred ten million, two hundred thirty-four thousand, one hundred seventeen".