Base | Representation |
---|---|
bin | 10011101100100001010010… |
… | …00111011010001100011101 |
3 | 12200100111121211001000110212 |
4 | 21312100221013122030131 |
5 | 21134102203321133041 |
6 | 232040510230142205 |
7 | 12060061265614535 |
oct | 1166205107321435 |
9 | 180314554030425 |
10 | 43311140021021 |
11 | 12889173471794 |
12 | 4a35ba51b1965 |
13 | 1b222b8b67682 |
14 | a9a3adc324c5 |
15 | 50194eb1b8eb |
hex | 2764291da31d |
43311140021021 has 2 divisors, whose sum is σ = 43311140021022. Its totient is φ = 43311140021020.
The previous prime is 43311140020997. The next prime is 43311140021041. The reversal of 43311140021021 is 12012004111334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26923500153796 + 16387639867225 = 5188786^2 + 4048165^2 .
It is a cyclic number.
It is not a de Polignac number, because 43311140021021 - 26 = 43311140020957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43311140021041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655570010510 + 21655570010511.
It is an arithmetic number, because the mean of its divisors is an integer number (21655570010511).
Almost surely, 243311140021021 is an apocalyptic number.
It is an amenable number.
43311140021021 is a deficient number, since it is larger than the sum of its proper divisors (1).
43311140021021 is an equidigital number, since it uses as much as digits as its factorization.
43311140021021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 43311140021021 its reverse (12012004111334), we get a palindrome (55323144132355).
The spelling of 43311140021021 in words is "forty-three trillion, three hundred eleven billion, one hundred forty million, twenty-one thousand, twenty-one".
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