43311214253 has 2 divisors, whose sum is σ = 43311214254. Its totient is φ = 43311214252.

The previous prime is 43311214217. The next prime is 43311214339. The reversal of 43311214253 is 35241211334.

43311214253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42101704969 + 1209509284 = 205187^2 + 34778^2 .

It is a cyclic number.

It is not a de Polignac number, because 43311214253 - 2¹² = 43311210157 is a prime.

It is a super-2 number, since 2×43311214253² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43311214753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655607126 + 21655607127.

It is an arithmetic number, because the mean of its divisors is an integer number (21655607127).

Almost surely, 2^43311214253 is an apocalyptic number.

It is an amenable number.

43311214253 is a deficient number, since it is larger than the sum of its proper divisors (1).

43311214253 is an equidigital number, since it uses as much as digits as its factorization.

43311214253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8640, while the sum is 29.

Adding to 43311214253 its reverse (35241211334), we get a palindrome (78552425587).

The spelling of 43311214253 in words is "forty-three billion, three hundred eleven million, two hundred fourteen thousand, two hundred fifty-three".