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4331141333221 is a prime number
BaseRepresentation
bin111111000001101100001…
…001000000000011100101
3120100001102200112100220011
4333001230021000003211
51031430134140130341
613113410542010221
7624625501620433
oct77015411000345
916301380470804
104331141333221
11141a91040849a
1259b4a2576971
1325556a5b2721
1410d8b2307d53
15779e2590b81
hex3f06c2400e5

4331141333221 has 2 divisors, whose sum is σ = 4331141333222. Its totient is φ = 4331141333220.

The previous prime is 4331141333203. The next prime is 4331141333243. The reversal of 4331141333221 is 1223331411334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2604253612900 + 1726887720321 = 1613770^2 + 1314111^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331141333221 - 211 = 4331141331173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331141333291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165570666610 + 2165570666611.

It is an arithmetic number, because the mean of its divisors is an integer number (2165570666611).

Almost surely, 24331141333221 is an apocalyptic number.

It is an amenable number.

4331141333221 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331141333221 is an equidigital number, since it uses as much as digits as its factorization.

4331141333221 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 31.

Adding to 4331141333221 its reverse (1223331411334), we get a palindrome (5554472744555).

The spelling of 4331141333221 in words is "four trillion, three hundred thirty-one billion, one hundred forty-one million, three hundred thirty-three thousand, two hundred twenty-one".