Base | Representation |
---|---|
bin | 1100100110101111111… |
… | …10111100000110000001 |
3 | 1112101221220022110120220 |
4 | 12103113332330012001 |
5 | 24044012301030423 |
6 | 530550035453253 |
7 | 43202061030132 |
oct | 6232776740601 |
9 | 1471856273526 |
10 | 433120330113 |
11 | 15775a153649 |
12 | 6bb37157229 |
13 | 31ac62c8c03 |
14 | 16d6abb7c89 |
15 | b3ee4349e3 |
hex | 64d7fbc181 |
433120330113 has 32 divisors (see below), whose sum is σ = 608841720960. Its totient is φ = 273488624640.
The previous prime is 433120330103. The next prime is 433120330117. The reversal of 433120330113 is 311033021334.
It is a happy number.
It is not a de Polignac number, because 433120330113 - 217 = 433120199041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (433120330117) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1250631 + ... + 1558947.
It is an arithmetic number, because the mean of its divisors is an integer number (19026303780).
Almost surely, 2433120330113 is an apocalyptic number.
It is an amenable number.
433120330113 is a deficient number, since it is larger than the sum of its proper divisors (175721390847).
433120330113 is a wasteful number, since it uses less digits than its factorization.
433120330113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 308657.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 433120330113 its reverse (311033021334), we get a palindrome (744153351447).
The spelling of 433120330113 in words is "four hundred thirty-three billion, one hundred twenty million, three hundred thirty thousand, one hundred thirteen".
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