43312121314027 has 2 divisors, whose sum is σ = 43312121314028. Its totient is φ = 43312121314026.

The previous prime is 43312121314003. The next prime is 43312121314031. The reversal of 43312121314027 is 72041312121334.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-43312121314027 is a prime.

It is a super-2 number, since 2×43312121314027² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43312121313983 and 43312121314001.

It is not a weakly prime, because it can be changed into another prime (43312121314037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21656060657013 + 21656060657014.

It is an arithmetic number, because the mean of its divisors is an integer number (21656060657014).

Almost surely, 2^{43312121314027} is an apocalyptic number.

43312121314027 is a deficient number, since it is larger than the sum of its proper divisors (1).

43312121314027 is an equidigital number, since it uses as much as digits as its factorization.

43312121314027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 34.

The spelling of 43312121314027 in words is "forty-three trillion, three hundred twelve billion, one hundred twenty-one million, three hundred fourteen thousand, twenty-seven".