Base | Representation |
---|---|
bin | 11001110100001… |
… | …111001100110101 |
3 | 1010011222222122011 |
4 | 121310033030311 |
5 | 1341334433044 |
6 | 110551204221 |
7 | 13506331423 |
oct | 3164171465 |
9 | 1104888564 |
10 | 433124149 |
11 | 20253a647 |
12 | 101076671 |
13 | 6b96b5a3 |
14 | 41748113 |
15 | 28058134 |
hex | 19d0f335 |
433124149 has 2 divisors, whose sum is σ = 433124150. Its totient is φ = 433124148.
The previous prime is 433124143. The next prime is 433124173. The reversal of 433124149 is 941421334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 421686225 + 11437924 = 20535^2 + 3382^2 .
It is a cyclic number.
It is not a de Polignac number, because 433124149 - 221 = 431026997 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 433124149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (433124143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216562074 + 216562075.
It is an arithmetic number, because the mean of its divisors is an integer number (216562075).
Almost surely, 2433124149 is an apocalyptic number.
It is an amenable number.
433124149 is a deficient number, since it is larger than the sum of its proper divisors (1).
433124149 is an equidigital number, since it uses as much as digits as its factorization.
433124149 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 31.
The square root of 433124149 is about 20811.6349429832. The cubic root of 433124149 is about 756.6077744880.
The spelling of 433124149 in words is "four hundred thirty-three million, one hundred twenty-four thousand, one hundred forty-nine".
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