Base | Representation |
---|---|
bin | 1100100110110000011… |
… | …01110000010111100010 |
3 | 1112101222011121210121112 |
4 | 12103120031300113202 |
5 | 24044014244323432 |
6 | 530550255023322 |
7 | 43202136035126 |
oct | 6233015602742 |
9 | 1471864553545 |
10 | 433124214242 |
11 | 157761366875 |
12 | 6bb3850ab42 |
13 | 31ac7058b05 |
14 | 16d6b509586 |
15 | b3ee9507b2 |
hex | 64d83705e2 |
433124214242 has 4 divisors (see below), whose sum is σ = 649686321366. Its totient is φ = 216562107120.
The previous prime is 433124214239. The next prime is 433124214253. The reversal of 433124214242 is 242412421334.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 242412421334 = 2 ⋅121206210667.
It can be written as a sum of positive squares in only one way, i.e., 316857535801 + 116266678441 = 562901^2 + 340979^2 .
It is a junction number, because it is equal to n+sod(n) for n = 433124214199 and 433124214208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108281053559 + ... + 108281053562.
Almost surely, 2433124214242 is an apocalyptic number.
433124214242 is a deficient number, since it is larger than the sum of its proper divisors (216562107124).
433124214242 is a wasteful number, since it uses less digits than its factorization.
433124214242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216562107123.
The product of its digits is 36864, while the sum is 32.
Adding to 433124214242 its reverse (242412421334), we get a palindrome (675536635576).
The spelling of 433124214242 in words is "four hundred thirty-three billion, one hundred twenty-four million, two hundred fourteen thousand, two hundred forty-two".
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