Base | Representation |
---|---|
bin | 111111000001110011100… |
… | …110111011111110001001 |
3 | 120100001202102021122212011 |
4 | 333001303212323332021 |
5 | 1031430413223340241 |
6 | 13113431215215521 |
7 | 624631552555033 |
oct | 77016346737611 |
9 | 16301672248764 |
10 | 4331266621321 |
11 | 141a975101282 |
12 | 59b5185175a1 |
13 | 25558a53b5b3 |
14 | 10d8c4bdcc53 |
15 | 779ed58d281 |
hex | 3f0739bbf89 |
4331266621321 has 2 divisors, whose sum is σ = 4331266621322. Its totient is φ = 4331266621320.
The previous prime is 4331266621309. The next prime is 4331266621397. The reversal of 4331266621321 is 1231266621334.
4331266621321 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2923398942025 + 1407867679296 = 1709795^2 + 1186536^2 .
It is a cyclic number.
It is not a de Polignac number, because 4331266621321 - 29 = 4331266620809 is a prime.
It is a super-3 number, since 3×43312666213213 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (4331266621921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165633310660 + 2165633310661.
It is an arithmetic number, because the mean of its divisors is an integer number (2165633310661).
Almost surely, 24331266621321 is an apocalyptic number.
It is an amenable number.
4331266621321 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331266621321 is an equidigital number, since it uses as much as digits as its factorization.
4331266621321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 40.
The spelling of 4331266621321 in words is "four trillion, three hundred thirty-one billion, two hundred sixty-six million, six hundred twenty-one thousand, three hundred twenty-one".
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