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4331266621397 is a prime number
BaseRepresentation
bin111111000001110011100…
…110111011111111010101
3120100001202102021122221222
4333001303212323333111
51031430413223341042
613113431215220125
7624631552555202
oct77016346737725
916301672248858
104331266621397
11141a975101341
1259b518517645
1325558a53b641
1410d8c4bdcca9
15779ed58d2d2
hex3f0739bbfd5

4331266621397 has 2 divisors, whose sum is σ = 4331266621398. Its totient is φ = 4331266621396.

The previous prime is 4331266621321. The next prime is 4331266621399. The reversal of 4331266621397 is 7931266621334.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4206596898001 + 124669723396 = 2050999^2 + 353086^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331266621397 - 214 = 4331266605013 is a prime.

Together with 4331266621399, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331266621399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165633310698 + 2165633310699.

It is an arithmetic number, because the mean of its divisors is an integer number (2165633310699).

Almost surely, 24331266621397 is an apocalyptic number.

It is an amenable number.

4331266621397 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331266621397 is an equidigital number, since it uses as much as digits as its factorization.

4331266621397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5878656, while the sum is 53.

The spelling of 4331266621397 in words is "four trillion, three hundred thirty-one billion, two hundred sixty-six million, six hundred twenty-one thousand, three hundred ninety-seven".