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43313040133 = 1131413097993
BaseRepresentation
bin101000010101101010…
…001000101100000101
311010210120010102011121
4220111222020230011
51202201114241013
631521524433541
73062223523636
oct502552105405
9133716112147
1043313040133
111740709a140
1284895488b1
13411357c13c
14214c5bd88d
1511d77b358d
hexa15a88b05

43313040133 has 16 divisors (see below), whose sum is σ = 49964447232. Its totient is φ = 37175904000.

The previous prime is 43313040119. The next prime is 43313040137. The reversal of 43313040133 is 33104031334.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 43313040133 - 29 = 43313039621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43313040098 and 43313040107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43313040137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1535016 + ... + 1562977.

It is an arithmetic number, because the mean of its divisors is an integer number (3122777952).

Almost surely, 243313040133 is an apocalyptic number.

It is an amenable number.

43313040133 is a deficient number, since it is larger than the sum of its proper divisors (6651407099).

43313040133 is a wasteful number, since it uses less digits than its factorization.

43313040133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3098076.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 43313040133 its reverse (33104031334), we get a palindrome (76417071467).

The spelling of 43313040133 in words is "forty-three billion, three hundred thirteen million, forty thousand, one hundred thirty-three".

Divisors: 1 11 31 41 341 451 1271 13981 3097993 34077923 96037783 127017713 1056415613 1397194843 3937549103 43313040133