Base | Representation |
---|---|
bin | 101000010101101010… |
… | …001000101100000101 |
3 | 11010210120010102011121 |
4 | 220111222020230011 |
5 | 1202201114241013 |
6 | 31521524433541 |
7 | 3062223523636 |
oct | 502552105405 |
9 | 133716112147 |
10 | 43313040133 |
11 | 1740709a140 |
12 | 84895488b1 |
13 | 411357c13c |
14 | 214c5bd88d |
15 | 11d77b358d |
hex | a15a88b05 |
43313040133 has 16 divisors (see below), whose sum is σ = 49964447232. Its totient is φ = 37175904000.
The previous prime is 43313040119. The next prime is 43313040137. The reversal of 43313040133 is 33104031334.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 43313040133 - 29 = 43313039621 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43313040098 and 43313040107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43313040137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1535016 + ... + 1562977.
It is an arithmetic number, because the mean of its divisors is an integer number (3122777952).
Almost surely, 243313040133 is an apocalyptic number.
It is an amenable number.
43313040133 is a deficient number, since it is larger than the sum of its proper divisors (6651407099).
43313040133 is a wasteful number, since it uses less digits than its factorization.
43313040133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3098076.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 43313040133 its reverse (33104031334), we get a palindrome (76417071467).
The spelling of 43313040133 in words is "forty-three billion, three hundred thirteen million, forty thousand, one hundred thirty-three".
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