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4331311010021 is a prime number
BaseRepresentation
bin111111000001110110010…
…000010001000011100101
3120100001212111210211201002
4333001312100101003211
51031431011104310041
613113435442443045
7624632632062122
oct77016620210345
916301774724632
104331311010021
11141a99816a156
1259b52b363485
132555967b08b8
1410d8caa75749
1577a0240a59b
hex3f0764110e5

4331311010021 has 2 divisors, whose sum is σ = 4331311010022. Its totient is φ = 4331311010020.

The previous prime is 4331311010017. The next prime is 4331311010029. The reversal of 4331311010021 is 1200101131334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2617555108996 + 1713755901025 = 1617886^2 + 1309105^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331311010021 - 22 = 4331311010017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4331311009975 and 4331311010002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331311010029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165655505010 + 2165655505011.

It is an arithmetic number, because the mean of its divisors is an integer number (2165655505011).

Almost surely, 24331311010021 is an apocalyptic number.

It is an amenable number.

4331311010021 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331311010021 is an equidigital number, since it uses as much as digits as its factorization.

4331311010021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 4331311010021 its reverse (1200101131334), we get a palindrome (5531412141355).

The spelling of 4331311010021 in words is "four trillion, three hundred thirty-one billion, three hundred eleven million, ten thousand, twenty-one".