Base | Representation |
---|---|
bin | 1100100110110001011… |
… | …00010101011011000100 |
3 | 1112101222201201001122001 |
4 | 12103120230111123010 |
5 | 24044023322332330 |
6 | 530551142515044 |
7 | 43202264132515 |
oct | 6233054253304 |
9 | 1471881631561 |
10 | 433132230340 |
11 | 157765941447 |
12 | 6bb3b135a84 |
13 | 31ac8904674 |
14 | 16d6c5d4a0c |
15 | b4004d59ca |
hex | 64d8b156c4 |
433132230340 has 48 divisors (see below), whose sum is σ = 943557108480. Its totient is φ = 166887601920.
The previous prime is 433132230317. The next prime is 433132230341. The reversal of 433132230340 is 43032231334.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 433132230299 and 433132230308.
It is not an unprimeable number, because it can be changed into a prime (433132230341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3278322 + ... + 3407881.
It is an arithmetic number, because the mean of its divisors is an integer number (19657439760).
Almost surely, 2433132230340 is an apocalyptic number.
It is an amenable number.
433132230340 is an abundant number, since it is smaller than the sum of its proper divisors (510424878140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
433132230340 is a wasteful number, since it uses less digits than its factorization.
433132230340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6686332 (or 6686330 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 433132230340 its reverse (43032231334), we get a palindrome (476164461674).
The spelling of 433132230340 in words is "four hundred thirty-three billion, one hundred thirty-two million, two hundred thirty thousand, three hundred forty".
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