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433132230397 is a prime number
BaseRepresentation
bin1100100110110001011…
…00010101011011111101
31112101222201201001201011
412103120230111123331
524044023322333042
6530551142515221
743202264132626
oct6233054253375
91471881631634
10433132230397
11157765941499
126bb3b135b11
1331ac89046b9
1416d6c5d4a4d
15b4004d5a17
hex64d8b156fd

433132230397 has 2 divisors, whose sum is σ = 433132230398. Its totient is φ = 433132230396.

The previous prime is 433132230353. The next prime is 433132230451. The reversal of 433132230397 is 793032231334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 418882078521 + 14250151876 = 647211^2 + 119374^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-433132230397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433132230317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216566115198 + 216566115199.

It is an arithmetic number, because the mean of its divisors is an integer number (216566115199).

Almost surely, 2433132230397 is an apocalyptic number.

It is an amenable number.

433132230397 is a deficient number, since it is larger than the sum of its proper divisors (1).

433132230397 is an equidigital number, since it uses as much as digits as its factorization.

433132230397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 244944, while the sum is 40.

The spelling of 433132230397 in words is "four hundred thirty-three billion, one hundred thirty-two million, two hundred thirty thousand, three hundred ninety-seven".