Base | Representation |
---|---|
bin | 101000010101101110… |
… | …001100000010000111 |
3 | 11010210122010101100002 |
4 | 220111232030002013 |
5 | 1202201402234112 |
6 | 31522003311515 |
7 | 3062235536642 |
oct | 502556140207 |
9 | 133718111302 |
10 | 43314102407 |
11 | 17407755254 |
12 | 848997b59b |
13 | 41138617c4 |
14 | 214c7b8a59 |
15 | 11d79231c2 |
hex | a15b8c087 |
43314102407 has 2 divisors, whose sum is σ = 43314102408. Its totient is φ = 43314102406.
The previous prime is 43314102301. The next prime is 43314102449. The reversal of 43314102407 is 70420141334.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43314102407 is a prime.
It is a super-2 number, since 2×433141024072 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43314102407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43314152407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657051203 + 21657051204.
It is an arithmetic number, because the mean of its divisors is an integer number (21657051204).
Almost surely, 243314102407 is an apocalyptic number.
43314102407 is a deficient number, since it is larger than the sum of its proper divisors (1).
43314102407 is an equidigital number, since it uses as much as digits as its factorization.
43314102407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 29.
The spelling of 43314102407 in words is "forty-three billion, three hundred fourteen million, one hundred two thousand, four hundred seven".
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