43314312113 has 2 divisors, whose sum is σ = 43314312114. Its totient is φ = 43314312112.

The previous prime is 43314312091. The next prime is 43314312133. The reversal of 43314312113 is 31121341334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29511116944 + 13803195169 = 171788^2 + 117487^2 .

It is a cyclic number.

It is not a de Polignac number, because 43314312113 - 2²⁶ = 43247203249 is a prime.

It is a super-2 number, since 2×43314312113² (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43314312133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657156056 + 21657156057.

It is an arithmetic number, because the mean of its divisors is an integer number (21657156057).

Almost surely, 2^43314312113 is an apocalyptic number.

It is an amenable number.

43314312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43314312113 is an equidigital number, since it uses as much as digits as its factorization.

43314312113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 26.

Adding to 43314312113 its reverse (31121341334), we get a palindrome (74435653447).

The spelling of 43314312113 in words is "forty-three billion, three hundred fourteen million, three hundred twelve thousand, one hundred thirteen".