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43314312091 is a prime number
BaseRepresentation
bin101000010101101110…
…111111001110011011
311010210122112000222011
4220111232333032123
51202201430441331
631522012010351
73062240402161
oct502556771633
9133718460864
1043314312091
1117407888846
128489a609b7
13411390608b
14214c831231
1511d79653b1
hexa15bbf39b

43314312091 has 2 divisors, whose sum is σ = 43314312092. Its totient is φ = 43314312090.

The previous prime is 43314312089. The next prime is 43314312113. The reversal of 43314312091 is 19021341334.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 43314312091 - 21 = 43314312089 is a prime.

It is a super-2 number, since 2×433143120912 (a number of 22 digits) contains 22 as substring.

Together with 43314312089, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (43314312031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657156045 + 21657156046.

It is an arithmetic number, because the mean of its divisors is an integer number (21657156046).

Almost surely, 243314312091 is an apocalyptic number.

43314312091 is a deficient number, since it is larger than the sum of its proper divisors (1).

43314312091 is an equidigital number, since it uses as much as digits as its factorization.

43314312091 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 43314312091 in words is "forty-three billion, three hundred fourteen million, three hundred twelve thousand, ninety-one".