Base | Representation |
---|---|
bin | 101000010101101110… |
… | …111111001110011011 |
3 | 11010210122112000222011 |
4 | 220111232333032123 |
5 | 1202201430441331 |
6 | 31522012010351 |
7 | 3062240402161 |
oct | 502556771633 |
9 | 133718460864 |
10 | 43314312091 |
11 | 17407888846 |
12 | 8489a609b7 |
13 | 411390608b |
14 | 214c831231 |
15 | 11d79653b1 |
hex | a15bbf39b |
43314312091 has 2 divisors, whose sum is σ = 43314312092. Its totient is φ = 43314312090.
The previous prime is 43314312089. The next prime is 43314312113. The reversal of 43314312091 is 19021341334.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43314312091 - 21 = 43314312089 is a prime.
It is a super-2 number, since 2×433143120912 (a number of 22 digits) contains 22 as substring.
Together with 43314312089, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (43314312031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657156045 + 21657156046.
It is an arithmetic number, because the mean of its divisors is an integer number (21657156046).
Almost surely, 243314312091 is an apocalyptic number.
43314312091 is a deficient number, since it is larger than the sum of its proper divisors (1).
43314312091 is an equidigital number, since it uses as much as digits as its factorization.
43314312091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 43314312091 in words is "forty-three billion, three hundred fourteen million, three hundred twelve thousand, ninety-one".
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