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4331531401 is a prime number
BaseRepresentation
bin1000000100010110…
…11110110010001001
3102011212112121000221
410002023132302021
532332333001101
61553451430041
7212224260301
oct40213366211
912155477027
104331531401
11192304471a
12a0a755321
1354050c542
142d13b4601
151a5411aa1
hex1022dec89

4331531401 has 2 divisors, whose sum is σ = 4331531402. Its totient is φ = 4331531400.

The previous prime is 4331531381. The next prime is 4331531417. The reversal of 4331531401 is 1041351334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3751685001 + 579846400 = 61251^2 + 24080^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4331531401 is a prime.

It is not a weakly prime, because it can be changed into another prime (4331531471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165765700 + 2165765701.

It is an arithmetic number, because the mean of its divisors is an integer number (2165765701).

Almost surely, 24331531401 is an apocalyptic number.

It is an amenable number.

4331531401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331531401 is an equidigital number, since it uses as much as digits as its factorization.

4331531401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 4331531401 is about 65814.3707787289. The cubic root of 4331531401 is about 1630.0984046128.

Adding to 4331531401 its reverse (1041351334), we get a palindrome (5372882735).

The spelling of 4331531401 in words is "four billion, three hundred thirty-one million, five hundred thirty-one thousand, four hundred one".