Base | Representation |
---|---|
bin | 10011101100110001110110… |
… | …00100110000011100110001 |
3 | 12200101100120110110021000012 |
4 | 21312120323010300130301 |
5 | 21134223411000001400 |
6 | 232044540404104305 |
7 | 12060524521043552 |
oct | 1166307304603461 |
9 | 180340513407005 |
10 | 43320031250225 |
11 | 12891a163208a4 |
12 | 4a37866995095 |
13 | 1b230a4c22c42 |
14 | a9a9b4a12329 |
15 | 501cc04aed35 |
hex | 27663b130731 |
43320031250225 has 48 divisors (see below), whose sum is σ = 57334125976320. Its totient is φ = 32398126675200.
The previous prime is 43320031250201. The next prime is 43320031250263. The reversal of 43320031250225 is 52205213002334.
It is not a de Polignac number, because 43320031250225 - 28 = 43320031249969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43320031250191 and 43320031250200.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1573436 + ... + 9440114.
It is an arithmetic number, because the mean of its divisors is an integer number (1194460957840).
Almost surely, 243320031250225 is an apocalyptic number.
It is an amenable number.
43320031250225 is a deficient number, since it is larger than the sum of its proper divisors (14014094726095).
43320031250225 is a wasteful number, since it uses less digits than its factorization.
43320031250225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7866930 (or 7866925 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 43320031250225 its reverse (52205213002334), we get a palindrome (95525244252559).
The spelling of 43320031250225 in words is "forty-three trillion, three hundred twenty billion, thirty-one million, two hundred fifty thousand, two hundred twenty-five".
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