433201231 has 2 divisors, whose sum is σ = 433201232. Its totient is φ = 433201230.

The previous prime is 433201213. The next prime is 433201267. The reversal of 433201231 is 132102334.

Together with previous prime (433201213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 433201231 - 2⁷ = 433201103 is a prime.

It is a super-2 number, since 2×433201231² = 375326613079830722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 433201199 and 433201208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433201271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216600615 + 216600616.

It is an arithmetic number, because the mean of its divisors is an integer number (216600616).

Almost surely, 2^433201231 is an apocalyptic number.

433201231 is a deficient number, since it is larger than the sum of its proper divisors (1).

433201231 is an equidigital number, since it uses as much as digits as its factorization.

433201231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 433201231 is about 20813.4867573888. The cubic root of 433201231 is about 756.6526556776.

Adding to 433201231 its reverse (132102334), we get a palindrome (565303565).

It can be divided in two parts, 43320 and 1231, that added together give a triangular number (44551 = T₂₉₈).

The spelling of 433201231 in words is "four hundred thirty-three million, two hundred one thousand, two hundred thirty-one".