Base | Representation |
---|---|
bin | 101000010110000110… |
… | …101011110101101101 |
3 | 11010211002012122022002 |
4 | 220112012223311231 |
5 | 1202210023233031 |
6 | 31522353102045 |
7 | 3062344244126 |
oct | 502606536555 |
9 | 133732178262 |
10 | 43320524141 |
11 | 17410340a74 |
12 | 848bb57925 |
13 | 4114c9c74b |
14 | 214d5ab04d |
15 | 11d8290ccb |
hex | a161abd6d |
43320524141 has 2 divisors, whose sum is σ = 43320524142. Its totient is φ = 43320524140.
The previous prime is 43320524099. The next prime is 43320524171. The reversal of 43320524141 is 14142502334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42615409225 + 705114916 = 206435^2 + 26554^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43320524141 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43320524171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21660262070 + 21660262071.
It is an arithmetic number, because the mean of its divisors is an integer number (21660262071).
Almost surely, 243320524141 is an apocalyptic number.
It is an amenable number.
43320524141 is a deficient number, since it is larger than the sum of its proper divisors (1).
43320524141 is an equidigital number, since it uses as much as digits as its factorization.
43320524141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
The spelling of 43320524141 in words is "forty-three billion, three hundred twenty million, five hundred twenty-four thousand, one hundred forty-one".
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