Base | Representation |
---|---|
bin | 111111000010101100011… |
… | …011111101100011110001 |
3 | 120100011012212022122000202 |
4 | 333002230123331203301 |
5 | 1031434341312424203 |
6 | 13114105554324545 |
7 | 624664310542361 |
oct | 77025433754361 |
9 | 16304185278022 |
10 | 4332220045553 |
11 | 1420314302a94 |
12 | 59b743889755 |
13 | 2556acc1bb4a |
14 | 10d9756a49a1 |
15 | 77a5711e388 |
hex | 3f0ac6fd8f1 |
4332220045553 has 2 divisors, whose sum is σ = 4332220045554. Its totient is φ = 4332220045552.
The previous prime is 4332220045529. The next prime is 4332220045639. The reversal of 4332220045553 is 3555400222334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3320310797584 + 1011909247969 = 1822172^2 + 1005937^2 .
It is a cyclic number.
It is not a de Polignac number, because 4332220045553 - 216 = 4332219980017 is a prime.
It is not a weakly prime, because it can be changed into another prime (4332220045523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166110022776 + 2166110022777.
It is an arithmetic number, because the mean of its divisors is an integer number (2166110022777).
Almost surely, 24332220045553 is an apocalyptic number.
It is an amenable number.
4332220045553 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332220045553 is an equidigital number, since it uses as much as digits as its factorization.
4332220045553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432000, while the sum is 38.
Adding to 4332220045553 its reverse (3555400222334), we get a palindrome (7887620267887).
The spelling of 4332220045553 in words is "four trillion, three hundred thirty-two billion, two hundred twenty million, forty-five thousand, five hundred fifty-three".
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