Base | Representation |
---|---|
bin | 111111000010101110011… |
… | …101011111011111000011 |
3 | 120100011022020012202021021 |
4 | 333002232131133133003 |
5 | 1031434424011013331 |
6 | 13114113210210311 |
7 | 624665202264202 |
oct | 77025635373703 |
9 | 16304266182237 |
10 | 4332254001091 |
11 | 1420331495315 |
12 | 59b753123997 |
13 | 2556b6c7a393 |
14 | 10d979dc3239 |
15 | 77a5a0ca211 |
hex | 3f0ae75f7c3 |
4332254001091 has 2 divisors, whose sum is σ = 4332254001092. Its totient is φ = 4332254001090.
The previous prime is 4332254001013. The next prime is 4332254001109. The reversal of 4332254001091 is 1901004522334.
Together with next prime (4332254001109) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4332254001091 - 29 = 4332254000579 is a prime.
It is not a weakly prime, because it can be changed into another prime (4332254091091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166127000545 + 2166127000546.
It is an arithmetic number, because the mean of its divisors is an integer number (2166127000546).
Almost surely, 24332254001091 is an apocalyptic number.
4332254001091 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332254001091 is an equidigital number, since it uses as much as digits as its factorization.
4332254001091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 34.
The spelling of 4332254001091 in words is "four trillion, three hundred thirty-two billion, two hundred fifty-four million, one thousand, ninety-one".
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