Base | Representation |
---|---|
bin | 111111000010111101010… |
… | …001100110000001101001 |
3 | 120100011221112212212002121 |
4 | 333002331101212001221 |
5 | 1031440431122243033 |
6 | 13114154005231241 |
7 | 625004310653446 |
oct | 77027521460151 |
9 | 16304845785077 |
10 | 4332502540393 |
11 | 14204498105a5 |
12 | 59b802402521 |
13 | 2557265cac61 |
14 | 10d9a0ddc9cd |
15 | 77a71d2162d |
hex | 3f0bd466069 |
4332502540393 has 2 divisors, whose sum is σ = 4332502540394. Its totient is φ = 4332502540392.
The previous prime is 4332502540391. The next prime is 4332502540439. The reversal of 4332502540393 is 3930452052334.
4332502540393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2627942514649 + 1704560025744 = 1621093^2 + 1305588^2 .
It is a cyclic number.
It is not a de Polignac number, because 4332502540393 - 21 = 4332502540391 is a prime.
Together with 4332502540391, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4332502540391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166251270196 + 2166251270197.
It is an arithmetic number, because the mean of its divisors is an integer number (2166251270197).
Almost surely, 24332502540393 is an apocalyptic number.
It is an amenable number.
4332502540393 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332502540393 is an equidigital number, since it uses as much as digits as its factorization.
4332502540393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1166400, while the sum is 43.
The spelling of 4332502540393 in words is "four trillion, three hundred thirty-two billion, five hundred two million, five hundred forty thousand, three hundred ninety-three".
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