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43325222137 is a prime number
BaseRepresentation
bin101000010110011000…
…100110110011111001
311010211102001022201221
4220112120212303321
51202212224102022
631523041512041
73062432211661
oct502630466371
9133742038657
1043325222137
1117412a5a70a
128491642621
134115c55c22
1421500711a1
1511d88bccc7
hexa16626cf9

43325222137 has 2 divisors, whose sum is σ = 43325222138. Its totient is φ = 43325222136.

The previous prime is 43325222081. The next prime is 43325222173. The reversal of 43325222137 is 73122252334.

43325222137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (43325222173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42029510121 + 1295712016 = 205011^2 + 35996^2 .

It is a cyclic number.

It is not a de Polignac number, because 43325222137 - 211 = 43325220089 is a prime.

It is not a weakly prime, because it can be changed into another prime (43325222737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21662611068 + 21662611069.

It is an arithmetic number, because the mean of its divisors is an integer number (21662611069).

Almost surely, 243325222137 is an apocalyptic number.

It is an amenable number.

43325222137 is a deficient number, since it is larger than the sum of its proper divisors (1).

43325222137 is an equidigital number, since it uses as much as digits as its factorization.

43325222137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 34.

The spelling of 43325222137 in words is "forty-three billion, three hundred twenty-five million, two hundred twenty-two thousand, one hundred thirty-seven".