Base | Representation |
---|---|
bin | 111111000010111111100… |
… | …001011101110001101101 |
3 | 120100012001011211222021112 |
4 | 333002333201131301231 |
5 | 1031441020301132331 |
6 | 13114201433441405 |
7 | 625005246353534 |
oct | 77027741356155 |
9 | 16305034758245 |
10 | 4332540255341 |
11 | 1420469030381 |
12 | 59b812b70265 |
13 | 2557313746ac |
14 | 10d9a601931b |
15 | 77a752c132b |
hex | 3f0bf85dc6d |
4332540255341 has 2 divisors, whose sum is σ = 4332540255342. Its totient is φ = 4332540255340.
The previous prime is 4332540255319. The next prime is 4332540255347. The reversal of 4332540255341 is 1435520452334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3760384167241 + 572156088100 = 1939171^2 + 756410^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4332540255341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4332540255347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166270127670 + 2166270127671.
It is an arithmetic number, because the mean of its divisors is an integer number (2166270127671).
Almost surely, 24332540255341 is an apocalyptic number.
It is an amenable number.
4332540255341 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332540255341 is an equidigital number, since it uses as much as digits as its factorization.
4332540255341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 41.
The spelling of 4332540255341 in words is "four trillion, three hundred thirty-two billion, five hundred forty million, two hundred fifty-five thousand, three hundred forty-one".
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