4333220544041 has 2 divisors, whose sum is σ = 4333220544042. Its totient is φ = 4333220544040.

The previous prime is 4333220544011. The next prime is 4333220544043. The reversal of 4333220544041 is 1404450223334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2982269955625 + 1350950588416 = 1726925^2 + 1162304^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4333220544041 is a prime.

Together with 4333220544043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4333220543992 and 4333220544010.

It is not a weakly prime, because it can be changed into another prime (4333220544043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166610272020 + 2166610272021.

It is an arithmetic number, because the mean of its divisors is an integer number (2166610272021).

Almost surely, 2^{4333220544041} is an apocalyptic number.

It is an amenable number.

4333220544041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4333220544041 is an equidigital number, since it uses as much as digits as its factorization.

4333220544041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138240, while the sum is 35.

Adding to 4333220544041 its reverse (1404450223334), we get a palindrome (5737670767375).

The spelling of 4333220544041 in words is "four trillion, three hundred thirty-three billion, two hundred twenty million, five hundred forty-four thousand, forty-one".