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433400041316381 is a prime number
BaseRepresentation
bin110001010001011001100111…
…1100000100010000000011101
32002211112122021001112121111012
41202202303033200202000131
5423301311241034111011
64133433121431305005
7160201056022556606
oct14242631740420035
92084478231477435
10433400041316381
11116104a1a675397
12407379b8b1b165
13157aa5aa562c99
147904961366dad
153518ae29a6a8b
hex18a2ccf82201d

433400041316381 has 2 divisors, whose sum is σ = 433400041316382. Its totient is φ = 433400041316380.

The previous prime is 433400041316329. The next prime is 433400041316423. The reversal of 433400041316381 is 183613140004334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 410796282972100 + 22603758344281 = 20268110^2 + 4754341^2 .

It is a cyclic number.

It is not a de Polignac number, because 433400041316381 - 246 = 363031297138717 is a prime.

It is a super-2 number, since 2×4334000413163812 (a number of 30 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433400041316311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216700020658190 + 216700020658191.

It is an arithmetic number, because the mean of its divisors is an integer number (216700020658191).

Almost surely, 2433400041316381 is an apocalyptic number.

It is an amenable number.

433400041316381 is a deficient number, since it is larger than the sum of its proper divisors (1).

433400041316381 is an equidigital number, since it uses as much as digits as its factorization.

433400041316381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 41.

The spelling of 433400041316381 in words is "four hundred thirty-three trillion, four hundred billion, forty-one million, three hundred sixteen thousand, three hundred eighty-one".