Base | Representation |
---|---|
bin | 111111000100101111000… |
… | …011000001001010011110 |
3 | 120100100212120121000020012 |
4 | 333010233003001022132 |
5 | 1032003333244301024 |
6 | 13115111233123222 |
7 | 625102516226444 |
oct | 77045703011236 |
9 | 16310776530205 |
10 | 4334411322014 |
11 | 1421239214474 |
12 | 5a00556b9512 |
13 | 25596bbb7937 |
14 | 10db02710b94 |
15 | 77b346b650e |
hex | 3f12f0c129e |
4334411322014 has 16 divisors (see below), whose sum is σ = 6529231229760. Its totient is φ = 2158002053760.
The previous prime is 4334411321987. The next prime is 4334411322089. The reversal of 4334411322014 is 4102231144334.
4334411322014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×43344113220143 (a number of 39 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7543442 + ... + 8097674.
It is an arithmetic number, because the mean of its divisors is an integer number (408076951860).
Almost surely, 24334411322014 is an apocalyptic number.
4334411322014 is a deficient number, since it is larger than the sum of its proper divisors (2194819907746).
4334411322014 is a wasteful number, since it uses less digits than its factorization.
4334411322014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 570835.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 4334411322014 its reverse (4102231144334), we get a palindrome (8436642466348).
The spelling of 4334411322014 in words is "four trillion, three hundred thirty-four billion, four hundred eleven million, three hundred twenty-two thousand, fourteen".
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