Base | Representation |
---|---|
bin | 111111000100101111001… |
… | …110011111111000011101 |
3 | 120100100212210020220100201 |
4 | 333010233032133320131 |
5 | 1032003340032101141 |
6 | 13115111421423501 |
7 | 625102553632306 |
oct | 77045716377035 |
9 | 16310783226321 |
10 | 4334414331421 |
11 | 142123a98a489 |
12 | 5a005670ab91 |
13 | 25596c6cc655 |
14 | 10db02c957ad |
15 | 77b34aad031 |
hex | 3f12f39fe1d |
4334414331421 has 2 divisors, whose sum is σ = 4334414331422. Its totient is φ = 4334414331420.
The previous prime is 4334414331409. The next prime is 4334414331439. The reversal of 4334414331421 is 1241334144334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3013397415396 + 1321016916025 = 1735914^2 + 1149355^2 .
It is a cyclic number.
It is not a de Polignac number, because 4334414331421 - 219 = 4334413807133 is a prime.
It is a super-3 number, since 3×43344143314213 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4334414331461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2167207165710 + 2167207165711.
It is an arithmetic number, because the mean of its divisors is an integer number (2167207165711).
Almost surely, 24334414331421 is an apocalyptic number.
It is an amenable number.
4334414331421 is a deficient number, since it is larger than the sum of its proper divisors (1).
4334414331421 is an equidigital number, since it uses as much as digits as its factorization.
4334414331421 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 165888, while the sum is 37.
Adding to 4334414331421 its reverse (1241334144334), we get a palindrome (5575748475755).
The spelling of 4334414331421 in words is "four trillion, three hundred thirty-four billion, four hundred fourteen million, three hundred thirty-one thousand, four hundred twenty-one".
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