Base | Representation |
---|---|
bin | 1010010101100… |
… | …0101110100001 |
3 | 10000120122221021 |
4 | 2211120232201 |
5 | 42044330131 |
6 | 4145125441 |
7 | 1034340352 |
oct | 245305641 |
9 | 100518837 |
10 | 43355041 |
11 | 22522314 |
12 | 12629881 |
13 | 8c9c992 |
14 | 5a87d29 |
15 | 3c15e11 |
hex | 2958ba1 |
43355041 has 2 divisors, whose sum is σ = 43355042. Its totient is φ = 43355040.
The previous prime is 43355027. The next prime is 43355047. The reversal of 43355041 is 14055334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25715041 + 17640000 = 5071^2 + 4200^2 .
It is a cyclic number.
It is not a de Polignac number, because 43355041 - 29 = 43354529 is a prime.
It is a super-2 number, since 2×433550412 = 3759319160223362, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43354997 and 43355015.
It is not a weakly prime, because it can be changed into another prime (43355047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21677520 + 21677521.
It is an arithmetic number, because the mean of its divisors is an integer number (21677521).
Almost surely, 243355041 is an apocalyptic number.
It is an amenable number.
43355041 is a deficient number, since it is larger than the sum of its proper divisors (1).
43355041 is an equidigital number, since it uses as much as digits as its factorization.
43355041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 25.
The square root of 43355041 is about 6584.4544952486. The cubic root of 43355041 is about 351.3013891201.
The spelling of 43355041 in words is "forty-three million, three hundred fifty-five thousand, forty-one".
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