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4336402317053 is a prime number
BaseRepresentation
bin111111000110100101101…
…110000011111011111101
3120100120000100000000222012
4333012211232003323331
51032021422443121203
613120040555101005
7625203043344632
oct77064556037375
916316010000865
104336402317053
111422070070514
125a0510441765
13255bc852b301
1410dc50d04189
1577bee39abd8
hex3f1a5b83efd

4336402317053 has 2 divisors, whose sum is σ = 4336402317054. Its totient is φ = 4336402317052.

The previous prime is 4336402316923. The next prime is 4336402317127. The reversal of 4336402317053 is 3507132046334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4330136486404 + 6265830649 = 2080898^2 + 79157^2 .

It is a cyclic number.

It is not a de Polignac number, because 4336402317053 - 218 = 4336402054909 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4336402317053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4336402317253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2168201158526 + 2168201158527.

It is an arithmetic number, because the mean of its divisors is an integer number (2168201158527).

Almost surely, 24336402317053 is an apocalyptic number.

It is an amenable number.

4336402317053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4336402317053 is an equidigital number, since it uses as much as digits as its factorization.

4336402317053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 41.

The spelling of 4336402317053 in words is "four trillion, three hundred thirty-six billion, four hundred two million, three hundred seventeen thousand, fifty-three".