Base | Representation |
---|---|
bin | 10011101111001001010011… |
… | …00010011010100000111001 |
3 | 12200200010110002212112001102 |
4 | 21313210221202122200321 |
5 | 21142041421400212213 |
6 | 232150145003101145 |
7 | 12066433462035143 |
oct | 1167445142324071 |
9 | 180603402775042 |
10 | 43401341413433 |
11 | 12913450836993 |
12 | 4a4b5795117b5 |
13 | 1b2a962610953 |
14 | aa08c9795c93 |
15 | 503e7d9ca158 |
hex | 27792989a839 |
43401341413433 has 2 divisors, whose sum is σ = 43401341413434. Its totient is φ = 43401341413432.
The previous prime is 43401341413379. The next prime is 43401341413439. The reversal of 43401341413433 is 33431414310434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29169796422649 + 14231544990784 = 5400907^2 + 3772472^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43401341413433 is a prime.
It is not a weakly prime, because it can be changed into another prime (43401341413439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21700670706716 + 21700670706717.
It is an arithmetic number, because the mean of its divisors is an integer number (21700670706717).
Almost surely, 243401341413433 is an apocalyptic number.
It is an amenable number.
43401341413433 is a deficient number, since it is larger than the sum of its proper divisors (1).
43401341413433 is an equidigital number, since it uses as much as digits as its factorization.
43401341413433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 38.
Adding to 43401341413433 its reverse (33431414310434), we get a palindrome (76832755723867).
The spelling of 43401341413433 in words is "forty-three trillion, four hundred one billion, three hundred forty-one million, four hundred thirteen thousand, four hundred thirty-three".
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