Base | Representation |
---|---|
bin | 111111001010000100001… |
… | …011001101100011010101 |
3 | 120100220122102202121021011 |
4 | 333022010023031203111 |
5 | 1032102043413004230 |
6 | 13121455200452221 |
7 | 625364402363263 |
oct | 77120413154325 |
9 | 16326572677234 |
10 | 4340134500565 |
11 | 14237058621a6 |
12 | 5a119231a071 |
13 | 25637180ca16 |
14 | 1100c6861433 |
15 | 77d6bd6ce2a |
hex | 3f2842cd8d5 |
4340134500565 has 32 divisors (see below), whose sum is σ = 5572294166880. Its totient is φ = 3233642840064.
The previous prime is 4340134500551. The next prime is 4340134500587. The reversal of 4340134500565 is 5650054310434.
4340134500565 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 16 ways, for example, as 253433710084 + 4086700790481 = 503422^2 + 2021559^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4340134500565 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53989321 + ... + 54069649.
It is an arithmetic number, because the mean of its divisors is an integer number (174134192715).
Almost surely, 24340134500565 is an apocalyptic number.
It is an amenable number.
4340134500565 is a deficient number, since it is larger than the sum of its proper divisors (1232159666315).
4340134500565 is a wasteful number, since it uses less digits than its factorization.
4340134500565 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87001.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 4340134500565 its reverse (5650054310434), we get a palindrome (9990188810999).
The spelling of 4340134500565 in words is "four trillion, three hundred forty billion, one hundred thirty-four million, five hundred thousand, five hundred sixty-five".
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