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4340139905249 is a prime number
BaseRepresentation
bin111111001010000100011…
…111110101000011100001
3120100220122210221012002122
4333022010133311003201
51032102101303431444
613121455512354025
7625364466333341
oct77120437650341
916326583835078
104340139905249
111423708913885
125a11940a5915
13256372982a65
141100c746ad21
1577d6c5894ee
hex3f2847f50e1

4340139905249 has 2 divisors, whose sum is σ = 4340139905250. Its totient is φ = 4340139905248.

The previous prime is 4340139905209. The next prime is 4340139905261. The reversal of 4340139905249 is 9425099310434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4215601495249 + 124538410000 = 2053193^2 + 352900^2 .

It is a cyclic number.

It is not a de Polignac number, because 4340139905249 - 228 = 4339871469793 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4340139905249.

It is not a weakly prime, because it can be changed into another prime (4340139905209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170069952624 + 2170069952625.

It is an arithmetic number, because the mean of its divisors is an integer number (2170069952625).

Almost surely, 24340139905249 is an apocalyptic number.

It is an amenable number.

4340139905249 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340139905249 is an equidigital number, since it uses as much as digits as its factorization.

4340139905249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4199040, while the sum is 53.

The spelling of 4340139905249 in words is "four trillion, three hundred forty billion, one hundred thirty-nine million, nine hundred five thousand, two hundred forty-nine".