434021112030053 has 2 divisors, whose sum is σ = 434021112030054. Its totient is φ = 434021112030052.

The previous prime is 434021112029929. The next prime is 434021112030091. The reversal of 434021112030053 is 350030211120434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 426528317163844 + 7492794866209 = 20652562^2 + 2737297^2 .

It is a cyclic number.

It is not a de Polignac number, because 434021112030053 - 2¹² = 434021112025957 is a prime.

It is a super-3 number, since 3×434021112030053³ (a number of 45 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 434021112029998 and 434021112030025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (434021112030353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217010556015026 + 217010556015027.

It is an arithmetic number, because the mean of its divisors is an integer number (217010556015027).

Almost surely, 2^{434021112030053} is an apocalyptic number.

It is an amenable number.

434021112030053 is a deficient number, since it is larger than the sum of its proper divisors (1).

434021112030053 is an equidigital number, since it uses as much as digits as its factorization.

434021112030053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 434021112030053 its reverse (350030211120434), we get a palindrome (784051323150487).

The spelling of 434021112030053 in words is "four hundred thirty-four trillion, twenty-one billion, one hundred twelve million, thirty thousand, fifty-three".