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4340214023417 is a prime number
BaseRepresentation
bin111111001010001000111…
…010100100010011111001
3120100220211222101210002222
4333022020322210103321
51032102224242222132
613121511121133425
7625366356331316
oct77121072442371
916326758353088
104340214023417
111423746737968
125a11b4a8a275
13256385133b6c
141100d3241d0d
1577d73d2a412
hex3f288ea44f9

4340214023417 has 2 divisors, whose sum is σ = 4340214023418. Its totient is φ = 4340214023416.

The previous prime is 4340214023401. The next prime is 4340214023419. The reversal of 4340214023417 is 7143204120434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4293892653241 + 46321370176 = 2072171^2 + 215224^2 .

It is a cyclic number.

It is not a de Polignac number, because 4340214023417 - 24 = 4340214023401 is a prime.

Together with 4340214023419, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4340214023419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170107011708 + 2170107011709.

It is an arithmetic number, because the mean of its divisors is an integer number (2170107011709).

Almost surely, 24340214023417 is an apocalyptic number.

It is an amenable number.

4340214023417 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340214023417 is an equidigital number, since it uses as much as digits as its factorization.

4340214023417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 35.

The spelling of 4340214023417 in words is "four trillion, three hundred forty billion, two hundred fourteen million, twenty-three thousand, four hundred seventeen".