Base | Representation |
---|---|
bin | 101000011010111110… |
… | …011010010001101011 |
3 | 11011000202222021221021 |
4 | 220122332122101223 |
5 | 1202341433204011 |
6 | 31534432353311 |
7 | 3064355651104 |
oct | 503276322153 |
9 | 134022867837 |
10 | 43402241131 |
11 | 17452485177 |
12 | 84b33a5837 |
13 | 4128bb14b2 |
14 | 215a39d3ab |
15 | 11e0533471 |
hex | a1af9a46b |
43402241131 has 2 divisors, whose sum is σ = 43402241132. Its totient is φ = 43402241130.
The previous prime is 43402241117. The next prime is 43402241173. The reversal of 43402241131 is 13114220434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43402241131 - 219 = 43401716843 is a prime.
It is a super-2 number, since 2×434022411312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43402241096 and 43402241105.
It is not a weakly prime, because it can be changed into another prime (43402241111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21701120565 + 21701120566.
It is an arithmetic number, because the mean of its divisors is an integer number (21701120566).
Almost surely, 243402241131 is an apocalyptic number.
43402241131 is a deficient number, since it is larger than the sum of its proper divisors (1).
43402241131 is an equidigital number, since it uses as much as digits as its factorization.
43402241131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 43402241131 its reverse (13114220434), we get a palindrome (56516461565).
The spelling of 43402241131 in words is "forty-three billion, four hundred two million, two hundred forty-one thousand, one hundred thirty-one".
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