Base | Representation |
---|---|
bin | 110001010101111111011100… |
… | …0110001101100000010001011 |
3 | 2002220202221221001111110211012 |
4 | 1202223332320301230002023 |
5 | 423342131012123133233 |
6 | 4135035033101154135 |
7 | 160264464202156031 |
oct | 14253767061540213 |
9 | 2086687831443735 |
10 | 434031020130443 |
11 | 11632858177545a |
12 | 4081a15255b94b |
13 | 15824c462b55a8 |
14 | 79272dba4a551 |
15 | 352a222347548 |
hex | 18abfb8c6c08b |
434031020130443 has 2 divisors, whose sum is σ = 434031020130444. Its totient is φ = 434031020130442.
The previous prime is 434031020130427. The next prime is 434031020130469. The reversal of 434031020130443 is 344031020130434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434031020130443 - 24 = 434031020130427 is a prime.
It is not a weakly prime, because it can be changed into another prime (434031020120443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217015510065221 + 217015510065222.
It is an arithmetic number, because the mean of its divisors is an integer number (217015510065222).
Almost surely, 2434031020130443 is an apocalyptic number.
434031020130443 is a deficient number, since it is larger than the sum of its proper divisors (1).
434031020130443 is an equidigital number, since it uses as much as digits as its factorization.
434031020130443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 434031020130443 its reverse (344031020130434), we get a palindrome (778062040260877).
Subtracting from 434031020130443 its reverse (344031020130434), we obtain a palindrome (90000000000009).
The spelling of 434031020130443 in words is "four hundred thirty-four trillion, thirty-one billion, twenty million, one hundred thirty thousand, four hundred forty-three".
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