Base | Representation |
---|---|
bin | 1000000101011001… |
… | …11111000000111001 |
3 | 102012111001210201122 |
4 | 10002230333000321 |
5 | 32342110023134 |
6 | 1554403555025 |
7 | 212362030112 |
oct | 40254770071 |
9 | 12174053648 |
10 | 4340314169 |
11 | 1927aa3304 |
12 | a1168ba75 |
13 | 542296049 |
14 | 2d261d209 |
15 | 1a609902e |
hex | 102b3f039 |
4340314169 has 2 divisors, whose sum is σ = 4340314170. Its totient is φ = 4340314168.
The previous prime is 4340314129. The next prime is 4340314171. The reversal of 4340314169 is 9614130434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4276506025 + 63808144 = 65395^2 + 7988^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4340314169 is a prime.
It is a super-2 number, since 2×43403141692 = 37676654171244321122, which contains 22 as substring.
Together with 4340314171, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4340314109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170157084 + 2170157085.
It is an arithmetic number, because the mean of its divisors is an integer number (2170157085).
Almost surely, 24340314169 is an apocalyptic number.
It is an amenable number.
4340314169 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340314169 is an equidigital number, since it uses as much as digits as its factorization.
4340314169 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The square root of 4340314169 is about 65881.0607762201. The cubic root of 4340314169 is about 1631.1994094125.
The spelling of 4340314169 in words is "four billion, three hundred forty million, three hundred fourteen thousand, one hundred sixty-nine".
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